One Sentence

Hugo theme OneSentence, using one sentence to describe your article, ported from hugo-ivy of YihuiXie.

Math Preview

Murray Bourne · 2019-03-04 · Words: 652


KaTeX and MathJax Comparison Demo, currently processed as KaTex

Repeating fractions

$$ \frac{1}{\Bigl(\sqrt{\phi \sqrt{5}}-\phi\Bigr) e^{\frac25 \pi}} \equiv 1+\frac{e^{-2\pi}} {1+\frac{e^{-4\pi}} {1+\frac{e^{-6\pi}} {1+\frac{e^{-8\pi}} {1+\cdots} } } } $$

Summation notation

$$ \left( \sum_{k=1}^n a_k b_k \right)^2 \leq \left( \sum_{k=1}^n a_k^2 \right) \left( \sum_{k=1}^n b_k^2 \right) $$

Sum of a Series

I broke up the next two examples into separate lines so it behaves better on a mobile phone. That’s why they include \displaystyle.

$$ \displaystyle\sum_{i=1}^{k+1}i $$

$$ \displaystyle= \left(\sum_{i=1}^{k}i\right) +(k+1) $$

$$ \displaystyle= \frac{k(k+1)}{2}+k+1 $$

$$ \displaystyle= \frac{k(k+1)+2(k+1)}{2} $$

$$ \displaystyle= \frac{(k+1)(k+2)}{2} $$

$$ \displaystyle= \frac{(k+1)((k+1)+1)}{2} $$

Product notation

$$ \displaystyle 1 + \frac{q^2}{(1-q)}+\frac{q^6}{(1-q)(1-q^2)}+\cdots = \displaystyle \prod_{j=0}^{\infty}\frac{1}{(1-q^{5j+2})(1-q^{5j+3})}, \displaystyle\text{ for }\lvert q\rvert < 1. $$

Inline math

And here is some in-line math: $$ k_{n+1} = n^2 + k_n^2 - k_{n-1} $$ , followed by some more text.

Greek Letters

$$ \Gamma\ \Delta\ \Theta\ \Lambda\ \Xi\ \Pi\ \Sigma\ \Upsilon\ \Phi\ \Psi\ \Omega \alpha\ \beta\ \gamma\ \delta\ \epsilon\ \zeta\ \eta\ \theta\ \iota\ \kappa\ \lambda\ \mu\ \nu\ \xi \ \omicron\ \pi\ \rho\ \sigma\ \tau\ \upsilon\ \phi\ \chi\ \psi\ \omega\ \varepsilon\ \vartheta\ \varpi\ \varrho\ \varsigma\ \varphi $$

Arrows

$$ \gets\ \to\ \leftarrow\ \rightarrow\ \uparrow\ \Uparrow\ \downarrow\ \Downarrow\ \updownarrow\ \Updownarrow $$

$$ \Leftarrow\ \Rightarrow\ \leftrightarrow\ \Leftrightarrow\ \mapsto\ \hookleftarrow \leftharpoonup\ \leftharpoondown\ \rightleftharpoons\ \longleftarrow\ \Longleftarrow\ \longrightarrow $$

$$ \Longrightarrow\ \longleftrightarrow\ \Longleftrightarrow\ \longmapsto\ \hookrightarrow\ \rightharpoonup $$

$$ \rightharpoondown\ \leadsto\ \nearrow\ \searrow\ \swarrow\ \nwarrow $$

Symbols

$$ \surd\ \barwedge\ \veebar\ \odot\ \oplus\ \otimes\ \oslash\ \circledcirc\ \boxdot\ \bigtriangleup $$

$$ \bigtriangledown\ \dagger\ \diamond\ \star\ \triangleleft\ \triangleright\ \angle\ \infty\ \prime\ \triangle $$

Calculus

$$ \int u \frac{dv}{dx},dx=uv-\int \frac{du}{dx}v,dx $$

$$ f(x) = \int_{-\infty}^\infty \hat f(\xi),e^{2 \pi i \xi x} $$

$$ \oint \vec{F} \cdot d\vec{s}=0 $$

Lorenz Equations

$$ \begin{aligned} \dot{x} & = \sigma(y-x) \ \dot{y} & = \rho x - y - xz \ \dot{z} & = -\beta z + xy \end{aligned} $$

Cross Product

This works in KaTeX, but the separation of fractions in this environment is not so good.

$$ \mathbf{V}_1 \times \mathbf{V}_2 = \begin{vmatrix} \mathbf{i} & \mathbf{j} & \mathbf{k} \ \frac{\partial X}{\partial u} & \frac{\partial Y}{\partial u} & 0 \ \frac{\partial X}{\partial v} & \frac{\partial Y}{\partial v} & 0 \end{vmatrix} $$

Here’s a workaround: make the fractions smaller with an extra class that targets the spans with “mfrac” class (makes no difference in the MathJax case):

$$ \mathbf{V}_1 \times \mathbf{V}_2 = \begin{vmatrix} \mathbf{i} & \mathbf{j} & \mathbf{k} \ \frac{\partial X}{\partial u} & \frac{\partial Y}{\partial u} & 0 \ \frac{\partial X}{\partial v} & \frac{\partial Y}{\partial v} & 0 \end{vmatrix} $$

Accents

$$ \hat{x}\ \vec{x}\ \ddot{x} $$

Stretchy brackets

$$ \left(\frac{x^2}{y^3}\right) $$

Evaluation at limits

$$ \left.\frac{x^3}{3}\right|_0^1 $$

Case definitions

$$ f(n) = \begin{cases} \frac{n}{2}, & \text{if } n\text{ is even} \ 3n+1, & \text{if } n\text{ is odd} \end{cases} $$

Maxwell’s Equations

$$ \begin{aligned} \nabla \times \vec{\mathbf{B}} -, \frac1c, \frac{\partial\vec{\mathbf{E}}}{\partial t} & = \frac{4\pi}{c}\vec{\mathbf{j}} \ \nabla \cdot \vec{\mathbf{E}} & = 4 \pi \rho \ \nabla \times \vec{\mathbf{E}}, +, \frac1c, \frac{\partial\vec{\mathbf{B}}}{\partial t} & = \vec{\mathbf{0}} \ \nabla \cdot \vec{\mathbf{B}} & = 0 \end{aligned} $$

These equations are quite cramped. We can add vertical spacing using (for example) [1em] after each line break (\). as you can see here:

$$ \begin{aligned} \nabla \times \vec{\mathbf{B}} -, \frac1c, \frac{\partial\vec{\mathbf{E}}}{\partial t} & = \frac{4\pi}{c}\vec{\mathbf{j}} \[1em] \nabla \cdot \vec{\mathbf{E}} & = 4 \pi \rho \[0.5em] \nabla \times \vec{\mathbf{E}}, +, \frac1c, \frac{\partial\vec{\mathbf{B}}}{\partial t} & = \vec{\mathbf{0}} \[1em] \nabla \cdot \vec{\mathbf{B}} & = 0 \end{aligned} $$

Statistics

Definition of combination:

$$ \frac{n!}{k!(n-k)!} = {^n}C_k {n \choose k} $$

Fractions on fractions

$$ \frac{\frac{1}{x}+\frac{1}{y}}{y-z} $$

n-th root

$$ \sqrt[n]{1+x+x^2+x^3+\ldots} $$

Matrices

$$ \begin{pmatrix} a_{11} & a_{12} & a_{13}\ a_{21} & a_{22} & a_{23}\ a_{31} & a_{32} & a_{33} \end{pmatrix} \begin{bmatrix} 0 & \cdots & 0 \ \vdots & \ddots & \vdots \ 0 & \cdots & 0 \end{bmatrix} $$

Punctuation

$$ f(x) = \sqrt{1+x} \quad (x \ge -1) f(x) \sim x^2 \quad (x\to\infty) $$

Now with punctuation:

$$ f(x) = \sqrt{1+x}, \quad x \ge -1 f(x) \sim x^2, \quad x\to\infty $$